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検索キーワード「a^3+b^3+c^3-3abc」に一致する投稿を表示しています

【ベストコレクション】 (a^2-b^2)^3+(b^2-c^2)^3+(c^2-a^2)^3/(a-b)^3+(b-c)^3+(c-a)^3 308762

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Factor (a^2b^2)^3(b^2c^2)^3(c^2a^2)^3 Use the Binomial Theorem Simplify each term Tap for more steps Multiply the exponents in Tap for more steps Apply the power rule and multiply exponents, Multiply by Rewrite using the commutative property of multiplication Multiply by7a2 b2 = (a b)(a – b ) 8a3 – b3 = (a – b) (a 2 ab b2 ) 9a3 b3 = (a b) (a 2 ab b2 ) 10(a b)2 (a b) 2 = 4ab 11(a b)2 (a b) 2 = 2(a 2 b2 ) 12If a b c =0, then a3 b3 c3 = 3 abc INDICES AND SURDS 1 am a n = a m n 2 am m n a an = − 3 (a ) am n mn= 4 (ab) a bm m m= 5 a am m b bmFor some m and n Thus, $E = (a b)(b c)(c a)m(a^2 b^2 c^2) n(ab bc ca)$ Inequalities From The Word 1995 05 (a^2-b^2)^3+(b^2-c^2)^3+(c^2-a^2)^3/(a-b)^3+(b-c)^3+(c-a)^3